we can tell a rectangle is also a square when both width and length are the same,
then,
solve for x
there is not solution, then the rectangle shown is not a square
The answer is C
if you put x and y in each equation it becomes true
Area = perimeter + 132.
Let each side of the city be x miles long, then:-
x^2 = 4x + 132
x^2 - 4x - 132 = 0
x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2
x = 13.66, -9.66 We ignore the negative
So the city has dimension of 13.66 * 13.66
13.7 * 13.7 to nearest 10th
Answer:
15.02
Step-by-step explanation:
24-8.98
okay so pretty much all you do to make the problem easier is to make the 24 a decimal as well (24.00) than just subtract like this:
24.00
- 8.98
Than once you've set it up like that, subtract. Start in the tenths place which is 0-8. you can't do that so you borrow from the ones place. and that is also 0, so you borrow from 4. than the 4, you cross it out and it turns into a 3, the 0 beside it, cross it out and put a 9 above it because the 0 beside it is borrowing. so now it'll be
23.90
- 8.98 (pretend the far right 0 is crossed out and has a 10 over it)
than you subtract and should get: 15.02
(it sounds weird im sorry explaining over this is complicating)