The triangle NET is an <em>isosceles</em> triangle as <u>ET</u> ≅ <u>TN</u> and ET = TN < EN given the condition that BEST is a <em>cyclic</em> quadrilateral.
<h3>How to determine the existence of an isosceles triangle</h3>
In this question we must apply <em>geometric</em> properties of angles and triangles to determine that the triangle NET is an <em>isosceles</em> triangle. <em>Isosceles</em> triangles are triangles with two sides of equal length. In addition, we must apply the geometric concept of proportionality.
Now we proceed to prove the existence of the isosceles triangle:
- <u>BE</u> ≅ <u>SN</u> Given
- ET is the bisector of ∠BES Given
- ET/ES = ET/EB Definition of proportionality
- ES = EB (3)
- <u>ES</u> ≅ <u>EB</u> Definition of congruence
- <u>ET</u> ≅ <u>TN</u> SSS Theorem/Result
Therefore, the triangle NET is an <em>isosceles</em> triangle as <u>ET</u> ≅ <u>TN</u> and ET = TN < EN given the condition that BEST is a <em>cyclic</em> quadrilateral. 
To learn more on isosceles triangles, we kindly invite to check this verified question: brainly.com/question/2456591
Um Hi It is $90 so type $90
Answer:
I don't know but if you figure it out tell me. Thanks
Step-by-step explanation:
Hello,
(2x^6-9x^5+4x^2-5)|x^3-5
-(2x^6-10x^3 ) | 2x^3 -9x^2 +10
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-9x^5 +10x^3 +4x^2-5
-(-9x^5+45x^2)
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10x^3-41x^2-5
-(10x^3-50)
-----------------
-41x²+45
Answer D
Answer: a is an element of set A. But p is not an element of set A.
Explanation: