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3 years ago

15

I need help please?!!!!!

1 answer:

Viefleur [7K]3 years ago

7 0

Answer: 9x+3

Step-by-step explanation: 4x-(-3 - 5x)

=4x+ 3 +5x [open the bracket]

=9x+3

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A fraction is written in simplest form when the GCF of the<br> numerator and the denominator is

Natasha_Volkova [10]

Answer:

simplified

Step-by-step explanation:

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2 years ago

Read 2 more answers

1.) Shapera is dividing 6,324 by 12. The first step in her calculation is shown here. What is the best explanation of what the n

Lilit [14]

Answer 2 is 12

Step-by-step explanation:

more than 11 is 12

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1 year ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

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Alex Ar [27]

Answer:

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Step-by-step explanation:

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2 years ago

Which of the following pairs of expressions could represent consecutive odd numbers?

iVinArrow [24]

N and n+2 because if n=1 then you do 1+2 and that equals 3. So then you have 1,3

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3 years ago