What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
1 answer:
Answer:
-1
Step-by-step explanation:
See the attachment for the polynomial long division. The constant in the quotient is -1.
_____
Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.
That could be a first guess in a "guess and check" solution approach.
<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).
<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2
Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.
You might be interested in
Answer:
No. It is not an Exponential Equation.
Step-by-step explanation:
Given
By the Definition of Exponential Equation which states.
"The equation is said to be an exponential equation when it has a variable occurred in the exponent and which have the same base."
For Example:
All given below are said to be exponential equations.
which can be rewritten as
Now in the given equation it doesn't have same base neither any means the base can be made same,hence the given equation is not an exponential equation