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Artist 52 [7]
3 years ago
12

What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

  -1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

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Step-by-step explanation:

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3 years ago
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Pls help put formula as well ( u don’t have too but if u can pls do ) giving brainliest !
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1. 198.56
Step-by-step explanation:
To find the volume of a cylinder, you need to find the area of the cross-section (one of the circles on the side) and multiply it by the length.
Area of the circle = π = π x (5.3/2) x (5.3/2) = π x 2.65 x 2.65 = 7.0225π
Volume of the cylinder = 7.0225π x 9 = 63.2025π = 198.56 2. V
=
a
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×
h

V
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π
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(
d
2
)
2
×
h

V
=
π
(
6.6
2
)
2
×
9.9

V
=
338.7
c
m
3

Hopefully this helps!
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3 years ago
Why is 378 a divisible by 3 and 9
goldenfox [79]
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