What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
1 answer:
Answer:
-1
Step-by-step explanation:
See the attachment for the polynomial long division. The constant in the quotient is -1.
_____
Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.
That could be a first guess in a "guess and check" solution approach.
<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).
<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2
Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.
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In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
<h3>What is the variables about?</h3>Note that:
y=-8x+4
y-4=-8x
(y-4)/-8=x
Since the independent variable x is known, one can switch the variable labels and thus it will be:
y=(x-4)/-8
f^-1(x)=(x-4)/-8
This can be written again as:
f^-1(x)=(4-x)/8 :P
Thus one can say No, as he forgot to switch the variable labels after solving for the independent variable.
In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
See the first part of the question below
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.
Learn more about variable from
#SPJ1
Answer:
2401
Step-by-step explanation:
Given that we want to estimate average income in a population.
The standard deviation of income in the population is $1,000
We want confidence interval around our estimate to be +/- $40
i.e Margin of error = 40
We know that margin of error = Std error * Z critical for 95%
i.e.
Std error =
Together we get