1. Here are the four steps of the statistical process in correct order:
1) Plan - <span>Form a question that can be answered by data.
2) Collect data - D</span><span>esign and implement a plan that collects data.
3) Process - </span><span>Analyze the data using graphical and numerical methods.
4) Present and discuss - </span><span>Interpret and compare the data.
So your answer is the last option.
2. I am definitely sure that </span><span>Edgar wrote a statistical, because every neighbor can give a different answer. A statistical question is the question which you don't expect to get only one answer. Instead of that you will get a variety of different answers.
3. According to what I've mentioned before, the only statement which shows a characteristic of a statistical question is: </span><span>There can be variability in the answers to the question.
4. I am completely sure that this one is statistical question: </span>How many hours do you spend each week training for a sports league? Because it could be answered with variability.
5. The only statistical question in his survey is: <span>How many hours do you spend at the food court each month?. Because it gives him more different answers for his survey.</span>
Answer:
(a) 8 balls
(b) 4 balls
Step-by-step explanation:
Let
Number of balls
For a box, the probability that there are N balls in it is:

For 2 boxes, it is:

From the question, we have:
Favorable outcome
To solve for N, we have:


Divide both sides by 2

Take log of both sides

Apply law of logarithm

Make N the subject


Approximate

Solving (b): Balls in one of the two boxes.
Here, we assume that each ball will have almost the same number of balls at a given instance;
Hence, we have:



<em>4 balls in each box</em>
Standard form means, move the variables to the left-hand-side and leave the constant all by herself on the right-hand-side, usually sorting the variables, so"x" goes first.
now, there's a denominator, we can do away with it, by simply multiplying both sides by the denominator, so let's do so,
Answer:
Exact Form:
1/25
Decimal Form:
0.04
Step-by-step explanation:
Make sure you multiply. That should get you to your answer.
Hope this helps.
Answer:
follows are the solution to this question:
Step-by-step explanation:
Please find the correct question in the attached file:
The formula for calculating the Confidence interval of proportion:


The number of learners with access to working at home on a computer:

Lower limit =0.48
upper limit = 0.60

