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makvit [3.9K]
3 years ago
7

Given the system of equations, what is the solution? x + 2y = 7 x - 2y = -1

Mathematics
1 answer:
Reika [66]3 years ago
4 0
Add the 2 equations to eliminate the 2y. We get

2x = 6

x = 3

Plug x = 3 into the first equation:-

3 + 2y = 7
2y = 7 - 3 = 4

y = 2


Answer is x = 3 and y = 2
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The following blueprint of a kitchen has dimensions of 7 inches by 7 inches. The island has been highlighted in red 3 1/2 The is
Talja [164]
So assuming 1 3/4 feet by feet means 1 3/4 feet by 1 foot,

island actual dimentions=1 3/4 feet by 1 foot

scale=1 inch=1 feet
logically, blueprints are smaller so for every real foot, 1 inch is drawn on the scale
so change every foot to inch

so the island on the blueprint=1 3/4 inch by 1 inch
6 0
3 years ago
Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1)
ioda

(1) Looks like the joint density is

f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1

\implies\boxed{c=\dfrac1{32}}

(2) The region in which <em>X</em> > 2 and <em>Y</em> < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

P(X>2,Y

(3) Are you supposed to find the marginal density of <em>X</em>, or the conditional density of <em>X</em> given <em>Y</em>?

In the first case, you simply integrate the joint density with respect to <em>y</em>:

f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0

In the second case, we instead first find the marginal density of <em>Y</em>:

f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0

Then use the marginal density to compute the conditional density of <em>X</em> given <em>Y</em>:

f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y

6 0
3 years ago
Is it the first second third or fourth.
svp [43]
It is the first answer
4 0
2 years ago
Read 2 more answers
One!<br> 2+1 = 23<br> 3+1 = 34<br> 4+2 = 26<br> 6+3 = 29<br> Then<br> 7+1 = ?<br> What’s the answer
Veronika [31]

Answer:78

Step-by-step explanation:

To get first digit 7 ➗ 1=7

To get second digit 7+1=8

3 0
3 years ago
On a number line that is 4 kilometer where is 4/3
Mariulka [41]
Find 4/3 of 4 kilometers...

to do this...

4*(4/3)

^^ this will give you your solution in km

Hope this helps



3 0
3 years ago
Read 2 more answers
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