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andrezito [222]
3 years ago
13

Which number line shows the solution to the inequality -4x + 3 < -5

Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:x>2

Step-by-step explanation:

4x/4>8/4

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Pablo Picasso obtained a loan of $2,400 to install a new roof on his home. The interest rate is 12% and the monthly payment is $
victus00 [196]
If you do 2,400 x .12 you get 288
You then need to do 288 and divide it by 12 and you get 24.
Your answer should be A. $24.00
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What is the effect on the graph of f(x) = 1 when it is transformed to
ivann1987 [24]

Answer: C) Shifted 16 units down

The minus 16 at the end is directly the reason why. Think of y = 1/x, and subtracting 16 from both sides to get y-16 = (1/x) - 16. The y-16 will shift every point down 16 units. For instance, the point (1, 1) moves to (1, -15).

5 0
3 years ago
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Cost $4 since 0.25•20=4. Together,they would cost Jada $6 , leaving her with $6 . 35 ounces of peanuts. If Jada wants 20 ounces
Viefleur [7K]

Answer:

The Answer is....

Step-by-step explanation:

Need more info and question needs to be explained better

6 0
3 years ago
The sum of two numbers is seventeen. Three less than three times the smaller is equal to the larger
tia_tia [17]
The numbers are 5 and 12.
Smaller number = x
Larger number = y
x +y =17
y = 3x - 3
x +3x -3 = 17
4x = 20
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8 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
2 years ago
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