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igor_vitrenko [27]
3 years ago
14

Please help me!!!!!!!​

Mathematics
2 answers:
noname [10]3 years ago
7 0

Answer:

D) 5 miles to 1 hour.

Step-by-step explanation:

If each small box is 1 mile you can count the boxes to line up with the 1 hour graph. Hence, 5 boxes to 1 hour box equals 5 miles to the hour.

andreyandreev [35.5K]3 years ago
7 0

Answer:

D.)5 miles to 1 hour

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What statement is NOT always true
Step2247 [10]
The statement "the diagonals are perpendicular ti each other" is sometimes true and sometimes false
8 0
3 years ago
What can you conclude about the population density from table provided
vaieri [72.5K]

The population density of an area is the number of people living in per unit area. The most populated region is Region A.

<h3>What is Population Density?</h3>

The population density of an area is the number of people living in per unit area. It is given by the formula,

\text{Population Density}=\dfrac{\text{Population of the area}}{\text{Total area}}

The population density of the different regions is as follows,

Region A = 20,178 person /521 km² = 38.729 person/km²

Region B = 1,200 person /451 km² = 2.66 person/km²

Region C = 13,475person /395 km² = 34.114 person/km²

Region D = 6,980 person /426 km² = 16.385 person/km²

Hence, The most populated region is Region A.

Learn more about Population Density:

brainly.com/question/1581160

#SPJ1

7 0
2 years ago
I beg for help where are the geniuses?
KatRina [158]

Answer:

CB = sqrt62

Step-by-step explanation:

The pythagorean theorem will help with this! First take triangle ACD, AD^2 + CD^2 = AC^2. Plug in, AD^2 + 16 = 25. AD^2  = 9. AD = 3. I'm not exactly sure how to find DB, but I can assume it's double of AD< so 6. We know CD is 4, so  4^2 + 6^2 = CB^2. 16 + 36 = CB^2. CB = sqrt62

Sorry if this isn't exactly right, there's no exact way to find DB.

7 0
3 years ago
0.386; 0.3; 0.683; 0.836<br>which Is greatest to least
Rus_ich [418]
Greatest to least:

0.836, 0.683, 0.386, 0.3
3 0
3 years ago
Read 2 more answers
If a and b are the roots of 11x^2-4x-2=0 then compute the product: (1+a+a^2+...)(1+b+b^2+...)
lisov135 [29]

Answer:

11/5

Step-by-step explanation:

FirLet a and b be the roots of 11x^2-4x-2=0

Now(1+a+a^2+\cdots)(1+b+b^2+\dcots)=\frac{1}{1-a}\cdot \frac{1}{1-b}\\=\frac{1}{(1-a)(1-b)}=\frac{1}{1-(a+b)+ab}

Dividing the quadratic equation by 11 we have

x^2-\frac{4}{11}x-\frac{2}{11}=0.

Now the sum of the roots is the minus of the coefficient of x and the product of the roots is the constant. Therefore

a+b = 4/11 \\ab = -2/11

and we have

\frac{1}{(1-a)(1-b)}=\frac{1}{1-\frac{4}{11}-\frac{2}{11}}\\=\frac{1}{(5/11)}=\frac{11}{5}

6 0
3 years ago
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