Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e









The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Every triangle’s inner angles’ addition equals to 180°
So if we find the x:
38°+x+2°+x=180°
40°+2x=180°
2x=180°-40°=140°
x=140°/2
x=70°
Now if we find the I hope this helped :)
Answer:
I GOT -42 SO LIKE 4 1/2
Step-by-step explanation:
Answer:
68cm^2
Step-by-step explanation:
Well there's not much to explain - the problem statement does it for us.
The surface area is equal to the sum of areas of the walls. There's 2 l*w walls, 2 l*h walls and 2 h*w walls.
SA = 2*l*h + 2*l*w + 2*h*w
SA = 2*4cm*6cm + 2*4cm*1cm + 2*6cm*1cm = 48cm^2 + 8cm^2 + 12cm^2 = 68cm^2