3x⁶y² + 57x⁵y³ + 252x⁴y⁴
= 3x⁴y²(x² + 19xy + 84y²)
= 3x⁴y²(x² + 12xy + 7xy + 84y²)
= 3x⁴y²(x(x + 12y) + 7y(x + 12y))
= 3x⁴y²(x + 12y)(x + 7y)
Answer:
0.93
Step-by-step explanation:
V=LWH (multiply the length, width and height)
So plug in the numbers, V=6x14x10=840 ft^3 (feet cube)
Answer:

Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m ×
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 

First make and equation. Since you want to find the number of the day where both charge the same total amount, you would make the equation:
let x= the number of days
110+46(x)=70+54(x)
Solve:
110-70+46(x)=70-70+54(x)
40+46(x)=54(x)
40+46(x)-46(x)=54(x)-46(x)
40=8(x)
40/8=8x/8
5=x
Therefore your answer would be 5 days