Answer:
Step-by-step explanation:
At the start of the day there are g pounds of gravel in the quarry.
Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.
Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.
Then it says that at this point, the amount of pounds in the mound are 1500. Hence we get
To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:
And so 
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15
That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
5 * 6 = 30
Conclusion for Area: After adding the results the answer should be 45.
The perimeter is solely adding all the sides together. You have a 10, two 5's, one 6, and two 3's. Add this together:
10 + 5 + 5 + 6 + 3 + 3 = 32
Conclusion for Perimeter: So the perimeter would be 32.
I hope this helps in someway, have a great rest of your day! ^ ^
| | Ghostgate | |
Answer: x = -2, y = 4
Step-by-step explanation:
Where the lines intersect on the graph.
X coordinate is x, Y coordinate is y.
Check the picture below.
includes 2, notice, it doesn't go below 2 over the y-axis, and then it keeps on going up. So, the range is from +2 onwards.
Answer:
19.1 miles
Step-by-step explanation:
The situation given represents a right triangle.
Thus, we would use trigonometric function to find how far north the boat travelled.
Let's represent how far the boat travelled north with "x".
Thus:
Reference angle = 23°
Opposite = x
Adjacent = 45 miles
Apply TOA:
Tan 23° = Opp/Adj
Tan 23° = x/45
Multiply both sides by 45
45 × Tan 23° = x
x = 45 × Tan 23°
x = 19.1013667
x = 19.1 miles (nearest tenth of a mile)
