Question

What is the slope of a line perpendicular to a line that contains the points (2,6) and (7, 2)?

Answer 1

Answer:

5/4 or 1.25

Step-by-step explanation:

Slope of the line containing (2,6) & (7,2):

m = (y2-y1)/(x2-x1)

m = (2-6)/(7-2)

= -4/5

For Perpendicular lines,

m1×m2 = -1

(-4/5)×m2 = -1

m2 = -1 × (-5/4)

m2 = 5/4 or 1.25