What is the slope of a line perpendicular to a line that contains the points (2,6) and (7, 2)?

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

5/4 or 1.25

Step-by-step explanation:

Slope of the line containing (2,6) & (7,2):

m = (y2-y1)/(x2-x1)

m = (2-6)/(7-2)

= -4/5

For Perpendicular lines,

m1×m2 = -1

(-4/5)×m2 = -1

m2 = -1 × (-5/4)

m2 = 5/4 or 1.25

You might be interested in

What is a area pls help

Lilit [14]

Answer:vArea is the quantity that expresses the extent of a two-dimensional figure or shape or planar lamina, in the plane. Surface area is its analog on the two-dimensional surface of a three-dimensional object.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Mrrafil [7]

Let the length of the rectangle is x. units , accordingly :

2.(x+3) = x×3.

2x + 6 = 3x.

x = 6 units is the answer :)

8 0

2 years ago

White lightbulbs are sold in packages of 9. Yellow lightbulbs are sold in packages of 12. Find the least number of lightbulbs of

AfilCa [17]

The least common multiple of each number is 36. So that is the answer. She will buy 4 packages of white and 3 packages of yellow bulbs.

5 0

2 years ago

Help please ASAP !!!

Arisa [49]

For this case we have that by definition of trigonometric relations of rectangular triangles, that the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle. So:

$Sin (45) = \frac {leg} {h}$