3 years ago

What is the slope of a line perpendicular to a line that contains the points (2,6) and (7, 2)?

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

5/4 or 1.25

Step-by-step explanation:

Slope of the line containing (2,6) & (7,2):

m = (y2-y1)/(x2-x1)

m = (2-6)/(7-2)

= -4/5

For Perpendicular lines,

m1×m2 = -1

(-4/5)×m2 = -1

m2 = -1 × (-5/4)

m2 = 5/4 or 1.25

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Find the value of annuity if the periodic deposit is $250 at 5% compounded quarterly for 10 years

mylen [45]

Answer:

The value of annuity is $P_v = \$ 7929.9$

Step-by-step explanation:

From the question we are told that

The periodic payment is $P = \$ 250$

The interest rate is $r = 5\% = 0.05$

Frequency at which it occurs in a year is n = 4 (quarterly )

The number of years is $t = 10 \ years$

The value of the annuity is mathematically represented as

$P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ]$ (reference EDUCBA website)

substituting values

$P_v = 250 * [1 - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]$

$P_v = 250 * [1 - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]$

$P_v = 250 * [0.3916 ] * [\frac{(1.0125)}{0.0125} ]$

$P_v = \$ 7929.9$

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3 years ago