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Lostsunrise [7]
3 years ago
12

What is the slope of a line perpendicular to a line that contains the points (2,6) and (7, 2)?

Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

5/4 or 1.25

Step-by-step explanation:

Slope of the line containing (2,6) & (7,2):

m = (y2-y1)/(x2-x1)

m = (2-6)/(7-2)

= -4/5

For Perpendicular lines,

m1×m2 = -1

(-4/5)×m2 = -1

m2 = -1 × (-5/4)

m2 = 5/4 or 1.25

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210 ways. This is a permutation question. Thus, insert 7P3 means 7 runners there is 3 places to be occupied. (7P3=210ways)
4 0
3 years ago
Example and answer,will give brain
Yuri [45]

Answer:

b) -2/5

Step-by-step explanation:

b is -2/5 because its negative and goes down at a rate of 0.4 or 2/5

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4 years ago
How many people will 5 pitchers serve if 1/8 pitcher serves 1 person?
miskamm [114]

Answer:

20 people

Step-by-step explanation:

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8 0
3 years ago
. A rectangular prism has a volume of 1374.28 inches. The prism is 9.4 inches wide and 17.2 inches long. What is the height of t
VashaNatasha [74]

Answer:

h = 8.5 inches

Step-by-step explanation:

Given that,

The volume of a rectangular prism = 1374.28 inches³

The prism is 9.4 inches wide and 17.2 inches long.

We need to find the height of the prism. We know that the formula for the volume of rectangular prism is given by :

V = lbh

Where

h is the height of the prism

So,

h=\dfrac{V}{lb}\\\\h=\dfrac{1374.28 }{9.4\times 17.2}\\\\h=8.5\ inches

So, the height of the prism is equal to 8.5 inches.

3 0
3 years ago
In Ms.Khans class,22 out of 25 students hand in their projects on time. What percent of the class hand in their projects on time
Nikitich [7]

88 % students of the class hand in their projects on time

<em><u>Solution:</u></em>

Given that, Ms.Khans class, 22 out of 25 students hand in their projects on time

Total number students = 25

Students hand in their projects on time = 22

<em><u>To find: percent of the class hand in their projects on time</u></em>

\text{ percent of class hand in time } = \frac{\text{Students hand in projects on time}}{\text{total students}} \times 100

Substituting the values, we get

\text{ percent of class hand in time } = \frac{22}{25} \times 100\\\\\text{ percent of class hand in time } = 0.88 \times 100\\\\\text{ percent of class hand in time } = 88

Thus 88 % students of the class hand in their projects on time

5 0
3 years ago
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