A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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Answer:
3 3/5 gallons per hour
Step-by-step explanation:
3/5 times 6 equals 18/5
18/5=3 3/5
Step-by-step explanation:
9514 1404 393
Answer:
$2.98
Step-by-step explanation:
The amount of interest earned is ...
I = P((1 +r)^t -1)
I = $9(1.1^3 -1) ≈ $2.98
Daniel will earn about $2.98 in interest in 3 years.
Answer:
True.
Step-by-step explanation:
y = -3x + 20
Put x as 5, then y output should be 5.
y = -3(5) + 20
y = -15 + 20
y = 5
True, the line with slope -3 passes through points (5, 5).
