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3 years ago

Solve the equation for x. show your work log(2x-6)=2

Mathematics

2 answers:

borishaifa [10]3 years ago

8 0

Answer:

x = e^2/2 + 3

Step-by-step explanation:

Solve for x:

log(2 x - 6) = 2

Hint: | Eliminate the logarithm from the left hand side.

Cancel logarithms by taking exp of both sides:

2 x - 6 = e^2

Hint: | Isolate terms with x to the left hand side.

Add 6 to both sides:

2 x = e^2 + 6

Hint: | Solve for x.

Divide both sides by 2:

Answer: x = e^2/2 + 3

Mrac [35]3 years ago

8 0

Answer:

x = 53

Step-by-step explanation:

Rewrite log ( 2 x − 6 ) = 2 in exponential form using the definition of a logarithm. If x and b are positive real numbers and b ≠ 1 , then log b ( x ) = y is equivalent to b y = x .

10 = x − 6

Solve for x .

Rewrite the equation as

x − 6 = 10 .

x − 6 = 10

Raise 10 to the power of 2 .

x − 6 = 100

Move all terms not containing x to the right side of the equation.

x = 106

Divide each term by 2 and simplify. x = 53

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List the markup and retail price of each item. Round to two decimal places when necessary. A shirt item price is $33.75 and the

kifflom [539]

Answer:

markup price = $25.31

retail price = $59.06

Step-by-step explanation:

Markup price is 75% OF 33.75

Retail price is original price (33.75) PLUS the markup price (to be found)

Firstly, converting a percentage to a decimal is simple. We simply divide by 100. So:

75% = 75/100 = 0.75

Now, to find markup, we multiply:

33.75 * 0.75 = $25.31

Now, the retail price is SUM of original and markup, that would be:

retail price = 33.75 + 25.31 = $59.06

Thus,

markup price = $25.31

retail price = $59.06

4 0

4 years ago

2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

3 0

4 years ago

Read 2 more answers

Find the measure of angle A.

dimaraw [331]

Answer:

60 degrees sorry if its wrong

Step-by-step explanation:

5 0

3 years ago

If f(x) = 1/6 x-8, then f^-1(x)=

bezimeni [28]

Answer:

f^-1(x) is 6x + 48

f(x) = 1/6x - 8

To find f^-1(x) equate f(x) to y

That's

f(x) = y

y = 1/6x - 8

Next interchange the terms

We have

x = 1/6y - 8

Make y the subject

Multiply through by 6

We have

6x = y - 48

y = 6x + 48

Therefore f^-1(x) is 6x + 48

Hope this helps you

5 0

3 years ago

Please answer...................................

vekshin1

Answer:

for the first one- 1/8 0.25= decimal and percent=12.5%

Second 8 boxes and shade in 6 0.75=decimal 75%

Step-by-step explanation:

8 0

4 years ago