Congruent figures Practice -2 measurement of angle F
1 answer:
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Answer:
The new compact tube is more likely to have a life length greater than 9000 hours.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Standard tube:
New compact tube:
1. Which fluorescent tube is more likely to have a life length greater than 9000 hours?
Whichever tube has the lower z-score when X = 9000, since the probability of having a life length greater than 9000 hours is 1 subtracted by the pvalue of Z when X = 9000. The higer z, the higher it's pvalue.
Standard tube:
New compact tube:
The new compact tube is more likely to have a life length greater than 9000 hours.