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7nadin3 [17]
3 years ago
11

Is it possible to have a deadlock involving only oneprocess? Explain your answer.

Computers and Technology
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

Hi!

It is not possible to have a deadlock involving only one process.

Explanation:

Deadlock is only possible if there are multiple processes trying to access the same shared resources. Another way to see it is if you have shared resources only can be a deadlock if multiple processes attempt to use it.

With only one process, you can use shared resources without the risk of fall into deadlock, but you don't have concurrence either.

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Question 2 In this question you are asked to calculate probabilties for the discrete uniform and exponential distribution. Make
sasho [114]

Answer:

Hi there! The question is asking to make changes to the H3_Q2.java program however there is no such program attached. Nevertheless, the requirements in the question can be addressed in a new H3_Q2.java program that i've listed below.

Explanation:

We can use the Scanner util in Java for prompting user input. The method nextInt() and nextDouble() allow only values of types "int" and "double" respectively. I have used the "switch" statement to direct the program based on user selection of menu item. The checks are printed with the "System.out.println" command and the program exits in case of error or invalid input. Finally, the calculation of probability simply requires you to replace the comment with the formula for the probability calculation based on the method chosen.

H3_Q2.java

import java.util.Scanner;

public class H3_Q2 {

 public static void main(String args[]) {

   // print main menu for user selection

   System.out.println("Please type 1 to select 'discrete uniform' or 2 to select 'exponential'");

   Scanner scan = new Scanner(System.in);

   int selection = scan.nextInt();

   switch(selection) {

     case 1:

       // discrete uniform

       System.out.println("Please enter a lower bound value a: ");

       int a = scan.nextInt();

       System.out.println("Please enter a upper bound value b: ");

       int b = scan.nextInt();

       System.out.println("Please enter a value x: ");

       int x = scan.nextInt();

       if (b <= a) {

         System.out.println("The upper bound value b should be greater than the lower bound value a");

         System.exit(0);

       }

       if (a > x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       if (b < x) {

         System.out.println("The value x should be greater than the lower bound value b");

         System.exit(0);

       }

       break;

     case 2:

       // exponential

       System.out.println("Please enter a lambda value for exponential: ");

       double lambda = scan.nextDouble();

       System.out.println("Please enter a value x: ");

       double d_x = scan.nextDouble();

       if (d_x <= 0.0) {

         System.out.println("The value x should be greater than 0");

         break;

       } else {

         // calculate P(X = x) and P(X ≤ x)

         // result = calculateExponential()

         System.out.println("The calculation for the exponential method given the lambda value " + lambda + " and the value of x " + d_x + " is: ");

       }

       break;

     default:

       System.out.println("Invalid input. Exiting..");

       break;

   }

 }

}

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Plsss help u will get brainliest
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Answer:

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Yare lively; eager; keen; agile; dexterous; ready; prepared.

Explanation:

got those ones hope it helps

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3 years ago
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