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2 years ago

I need help I don’t understand...

Mathematics

2 answers:

pentagon [3]2 years ago

7 0

Answer:

(1 , -2)

Step-by-step explanation:

The intersecting point of two lines is the solution

OLga [1]2 years ago

7 0

Answer: X→1(first blank) Y→-2(second blank) and or (1,-2)

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Winona’s bowling scores for the past nine weeks are 195, 180, 195, 212, 208, 231, 179, 246, and 195. Find the mean, median, and

belka [17]

Answer: Mean = 204.6 , Median = 195 and mode =195

Step-by-step explanation:

The given data for Winona’s bowling scores for the past nine weeks : 195, 180, 195, 212, 208, 231, 179, 246, 195.

The formula to find Mean is given by :-

$\text{Mean}=\dfrac{\text{Sum of all observations}}{\text{Number of observations}}\\\\=\dfrac{1841}{9}=204.555555556\approx204.6$

For median , first we arrange data values in order as

179, 180, 195, 195, 195, 208, 212, 231, 246

Since the number of data values is 9 (odd).

∴ Median = Middle most data value = 195

Also, Mode = Most occurring data value = 195

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2 years ago

Use your creativity... Write a short story/problem/question that can be described by the scenario of 4 divided by 1/2

vazorg [7]

Answer:

I was at the store getting groceries I saw that there was a sell on bags of candy The original price was 4.00 dollars The sale is 1/2 off a bag of candy what is the new price. The answer is 2.00 dollars.

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2 years ago

3 − (2x − 5) < −4(x + 2)<br><br> please help!!!!!!!!!

Flauer [41]

Just plug in an easy number for "x" and solve. Then see if the second problem is really greater that the first

7 0

2 years ago

Read 2 more answers

7 adult tickets and 7 kids tickets equal 50 dollars. Adult tickets are twice as expensive as the kid’s ticket. How much do the t

Shalnov [3]

Answer:

Cost Of Kid's tickets =16.66

Cost of Adult's tickets=33.34

Step-by-step explanation:

5 0

2 years ago

3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d

Alexxx [7]

Expand the right side:

$(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)$

$=ab^2x^3-b^2cx^2-ad^2x+cd^2$

Notice that 98 = 2 * 7 * 7, so we have $c=2$ and $d=7$ .

Then

$-ad^2=-147\implies a=\dfrac{147}{49}=3$

and

$ab^2=3\implies b^2=1\implies b=1$

6 0

2 years ago