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natulia [17]
3 years ago
7

If x+y = nx+2 then x equals

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

Hello,

Step-by-step explanation:

x+y=nx+2

x-nx=2-y

x(1-n)=2-y

if 1-n ≠0 (or n≠1) then

x=\dfrac{2-y}{1-x}

MaRussiya [10]3 years ago
5 0

Answer:

x+y =  nx+2

⇔x-nx = 2-y

⇔x(1-n) = 2-y

⇔x = (2-y)/(1-n)

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Match these equation balancing steps with the description of what was done in each step.
Alona [7]
Step 1: C. Step 2: A Step 3: B
3 0
2 years ago
Which inequality represents the sentence below? The difference of a number and one and four tenths is more than nine and seventy
Marianna [84]

The inequality represents the sentence below is that the p minus 1. 4 greater-than 9.

<h3>What is the inequality equation?</h3>

Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.

Given that the difference of a number and one and four tenths is more than nine and seventy-eight hundredths.

Before solving it, first let's discuss the tenth and hundredths,

  • Tenth is written as the fractional part of the number 10. The value of one tenth is equal to 1/10 or 0.1.
  • Hundredths is written as the fractional part of the number 100. The value of one hundredth is equal to 1/100 or 0.01.

Here, the sentence given that the difference of a number and one and four tenths is more than nine and seventy-eight hundredths.

One and four tenths can be written as,

1\dfrac{4}{10}

Nine and seventy-eight hundredths can be written as,

9\dfrac{78}{100}

Let suppose the number is <em>p</em>. This difference of this number and one four tenths is more than nine and seventy-eight hundredths. Thus,

p-1\dfrac{4}{10} > 9\dfrac{78}{100}\\p-\dfrac{14}{10} > \dfrac{978}{100}\\p-1.4 > 9.78\\

Hence, the inequality represents the sentence below is that the p minus 1. 4 greater-than 9.

Learn more about the inequality equation here:

brainly.com/question/17724536

3 0
2 years ago
Is it possible for three vectors of different magnitudes to add to zero?.
amid [387]

Answer:

No, it is not possible to obtain zero by adding two vectors of unequal magnitudes.

Explanation:

The Sum of two vectors can only be zero if they are equal in magnitude and opposite in direction. So no two vectors of unequal magnitude cannot be added to give a null vector. Three vectors of equal magnitude and making an angle 120 degrees with each other gives a zero resultant.

6 0
2 years ago
Maria and jane bought a whole pizza pie. marie ate 1/5 of the pie and jane ate 1/4 of the pie. write a number sentence to find o
Papessa [141]
Eleven Twentieths of the pie are left, so that's 11/20

Method to solve; 
Since its given a 1/4 and a 1/5 it's easiest to convert these to twentieths (the lowest common multiple of 4 and 5)
So 1/4= 5/20
      1/5 = 4/20
How much is eaten = 5/20 + 4/20 = 9/20
How much remains = Total (20/20) - How much eaten (9/20) = 11/20
8 0
3 years ago
Which equation represents a graph with a vertex at (–3, 2)?
lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> y= 4x^{2}+24x+38

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-38= 4x^{2}+24x

Factor the leading coefficient

y-38= 4(x^{2}+6x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-38+36= 4(x^{2}+6x+9)

y-2= 4(x+3)^{2}

y= 4(x+3)^{2}+2

<u>the vertex is the point (-3,2)</u>

<u>Part b)</u>  y=4x^{2}-24x+38

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-38= 4x^{2}-24x

Factor the leading coefficient

y-38= 4(x^{2}-6x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-38+36= 4(x^{2}-6x+9)

y-2= 4(x-3)^{2}

y= 4(x-3)^{2}+2

<u>the vertex is the point (3,2)</u>

<u>Part c) </u> y=4x^{2}+12x+2

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-2= 4x^{2}+12x

Factor the leading coefficient

y-2= 4(x^{2}+3x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-2+9= 4(x^{2}+3x+2.25)

y+7= 4(x+1.5)^{2}

y= 4(x+1.5)^{2}-7

<u>the vertex is the point (-1.5,7)</u>

<u>Part d)</u> y=4x^{2}+16x+13

Group terms that contain the same variable, and move the constant to the opposite side of the equation

y-13= 4x^{2}+16x

Factor the leading coefficient

y-13= 4(x^{2}+4x)

Complete the square. Remember to balance the equation by adding the same constants to each side

y-13+16= 4(x^{2}+4x+4)

y+3= 4(x+2)^{2}

y= 4(x+2)^{2}-3

<u>the vertex is the point (-2,-3)</u>

therefore

<u>the answer is </u>

y= 4x^{2}+24x+38

3 0
3 years ago
Read 2 more answers
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