I think it is two up and two right lol if that answers your question
Answer: 0.14
Step-by-step explanation:
You had to convert the decimals into percentages move the decimal point two places to the left which makes 14% the answer
I’m pretty sure the answer is 75.4 ft cubed.
Clearly, |S| = 50.
Count the multiples of 2 between 1 and 50:
⌊50/2⌋ = ⌊25⌋ = 25
(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round <u>down</u> to the nearest integer)
Count the multiples of 3 between 1 and 50:
⌊50/3⌋ ≈ ⌊16.667⌋ = 16
Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:
⌊50/6⌋ ≈ ⌊8.333⌋ = 8
Then by the inclusion/exclusion principle, we remove from S
25 + 16 - 8 = 33
elements, so that the new set S contains 50 - 33 = 17 elements.
X=original length of each side of the square.
perimeter: sum of all sides=4(length of the side)
The length of each side of the new square will be= (x-2)
we can suggest this equation:
4(x-2)=48
We solve this equation:
4(x-2)=48
4x-8=48
4x=48+8
4x=56
x=56/4
x=14
Answer: the original length of each side of the square would be 14 in.
