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iragen [17]
3 years ago
13

Julian sees a common denominator for 3 x 4 + 2

Mathematics
1 answer:
Rasek [7]3 years ago
7 0
the denominator would be 12
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john rode 2 kilometers on his 6ike.his sister sally rode 3000 meters on her bike.who rode the farthest and how much farther did
artcher [175]
1 kilometer is 1000 meters.  Therefore, 2 kilometers is 2000 meters.  2000 is greater than 3000, so Sally rode farther by 1000 meter, or 1 kilometer.
3 0
3 years ago
Please help :)))))))))))
olya-2409 [2.1K]

Answer:

Your answer is C and D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Marie, Shelia, and Martha bought snacks for a girl's sleepover. They each bought the items shown in the following table at the l
creativ13 [48]

Using a system of equations, it is found that the unit prices are:

  • $2.25 for a bag of chips.
  • $1.50 for a liter of pop.
  • $1.75 for a chocolate bar.

For the system:

  • x is the unit price of a bag of chips.
  • y is the unit price of liter of pop.
  • z is the unit price for a chocolate bar.

From the table, the equations are:

2x + 2y + z = 9.25

3x + 4y + z = 14.50

x + 3y + 3z = 12

Replacing the <u>first equation on the second and the third:</u>

z = 9.25 - 2x - 2y

3x + 4y + z = 14.50

3x + 4y + 9.25 - 2x - 2y = 14.50

x + 2y = 5.25

x = 5.25 - 2y

x + 3y + 3z = 12

x + 3y + 3(9.25 - 2x - 2y) = 12

-5x - 3y = -15.75

5x + 3y = 15.75

Since x = 5.25 - 2y:

5(5.25 - 2y) + 3y = 15.75

-7y = -10.5

y = \frac{10.5}{7}

y = 1.5

Then:

x = 5.25 - 2y = 5.25 - 2(1.5) = 2.25

z = 9.25 - 2x - 2y = 9.25 - 2(2.25) - 2(1.5) = 1.75

The unit prices are:

  • $2.25 for a bag of chips.
  • $1.50 for a liter of pop.
  • $1.75 for a chocolate bar.

A similar problem, also solved using a system of equations, is given at brainly.com/question/14183076

4 0
3 years ago
Find the non-extraneous solutions of the square root of the quantity x plus 6 minus 5 equals quantity x plus 1.
denis23 [38]
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous

3 0
3 years ago
Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you
Paul [167]

Answer:

a: no solutions

b: (2, 3)

Step-by-step explanation:

a:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

b:

Since both of the equations are equal to y, we can set them equal to each other:

\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

4 0
3 years ago
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