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2 years ago

Julian sees a common denominator for 3 x 4 + 2

Mathematics

1 answer:

Rasek [7]2 years ago

7 0

the denominator would be 12

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-11=-11a+33 what is the answer I’m stuck

Gnesinka [82]

A=4

The work behind it

-11a+33= -11
-33 -33

-11a=-44
Divide both sides by -11
-44/-11=a
A=4

5 0

3 years ago

The point slope form of the equaton of the line that passes through (-9, -2) and (1, 3) is y-3=1/2(x-1). What is the slope-inter

igomit [66]

Answer: y=1/2x+5/2

Step-by-step explanation:

y-3=1/2 (x-1)

y-3(-3)=1/2x-1/2(+3)

y=1/2x-1/2+6/2

y=1/2x+5/2

hope this helped!!

3 0

2 years ago

Find the product. (-5a ^2)^3·a ^5 A)-15a10 B)-125a11 C)15a6 D)-125a10

Ber [7]

Answer:

B) -125a^11

Step-by-step explanation:

(-5a^2)^3·a^5 = (-5)^3·a^6·a^5

= (-5)^3·a^(2·3)·a^5

= (-5)^3·a^6·a^5

= -125·a^(6+5)

= -125·a^11 . . . . matches choice B

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)^c = a^(bc)

5 0

2 years ago

Read 2 more answers

What is 6 times 3/8 in simplest form

agasfer [191]

6 times 3/8 is the same as:

6/1 * 3/8 

Now, multiply the tops and bottoms to get: 

18/8 

We can divide the top and bottom by 2, giving us: 

9/4

8 0

3 years ago

Read 2 more answers

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago