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NikAS [45]
3 years ago
11

HELPPP!!! ASAPP!!!!

Mathematics
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Hope this help

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A business manager who needs to make many phone calls has estimated that when she calls a client, the probability that she will
natka813 [3]

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a.  0.68 or 68%

b. 0.08 or 8%

c. 0.32 or 32%

Step-by-step explanation:

Probability of reaching client on the first call = 60%

Probability of reaching client on the second call = 20%

a. The probability that the manager reaches her client in two or fewer calls is the probability of reaching a client with one or two calls:

P(X\leq2) = P(X=1) +P(X=2)\\P(X\leq2) = 0.60+(1-0.60)*0.2\\P(X\leq2) = 0.68 = 68\%

b. The probability that the manager reaches her client on the second call but not on the first call is:

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c. The probability that manager is unsuccessful on two consecutive calls (needing more than two calls), P(X>2), is:

P(X>2) = 1-P(X\leq2) = 1-0.68\\P(X>2) = 0.32 = 32\%

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23% of 200 model please
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Answer:46

Step-by-step explanation:

7 0
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