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Sonja [21]
2 years ago
12

4) Cody invests $2,733 in a retirement

Mathematics
1 answer:
sasho [114]2 years ago
8 0

Answer:

t = 14 years

Step-by-step explanation:

r = R/100

r = 9/100

r = 0.09 per year,

Then, solve the equation for t

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(9,589.78/2,733.00) / ( 12 × [ln(1 + 0.09/12)] )

t = ln(9,589.78/2,733.00) / ( 12 × [ln(1 + 0.0075)] )

t = 14 years

Summary:

The time required to get a total amount of $9,589.78 with compoundeded interest on a principal of $2,733.00 at an interest rate of 9% per year and compounded 12 times per year is 14 years.

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Step-by-step explanation:

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write a story problem that can be solved by finding the sum of 506,211 and 424,809. then solve the problem
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<u>Story Problem</u>

Mr. Bill Gates bought a house in Italy for \$506,211 and a house in Canada for \$424,809. What is the total cost of the two houses?

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Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars
GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

<em>Let X = incomes for the industry</em>

So, X ~ N(\mu=95,\sigma^{2}=5^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

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            \sigma = standard deviation = 5 million dollars

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    P(X < 100) = P( \frac{X-\mu}{\sigma} < \frac{100-95}{5} ) = P(Z < 1) = 0.8413   {using z table]

                                                     

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

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