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2 years ago

12

Do the ratios 6/3 and 2/1 form a proportion?

2 answers:

antiseptic1488 [7]2 years ago

5 0

Answer:

Yes.

Step-by-step explanation:

Yes, because 6/3=2/1 since 6/3=2 and 2/1=2.

Tcecarenko [31]2 years ago

4 0

Answer:

Step-by-step explanation:

yes,

6x1=6

2x3=6

6/3=2/1

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Complete the solution of the equation find the value of y when x equals 2. -8x - 5y = -1

tatuchka [14]

Answer: y = -3

<u>Step-by-step explanation:</u>

-8x - 5y = -1

<u>+8x </u> <u>+8x </u>

-5y = 8x - 1

<u> ÷-5 </u> <u> ÷-5</u> <u>÷-5</u>

y = $-\frac{8}{5}x + \frac{1}{5}$

y(2) = $-\frac{8}{5}(2) + \frac{1}{5}$

= $-\frac{16}{5} + \frac{1}{5}$

= $-\frac{15}{5}$

= -3

6 0

3 years ago

Help with Math PLZ (Questions in screenshot)

-Dominant- [34]

1.) Let's say that the circle on the graph below represents x. The arrow is pointing to all the numbers greater than x, which happens to be on -2. If it points right, this means that x can equal to any number greater than -2. So your answer is x > -2.

2.) For inequalities such as these, you can simplify just like what you do for normal equations. Let's isolate x.

$x - 7 > 10$

--> $x > 10 + 7$

---> $x > 17$

3.) $3x \leq 21$

--> $\frac{3x}{3} \leq \frac{21}{3}$

---> $x \leq 7$

4.) $5a - 2 < 18$

--> $5a < 18 + 2$

---> $5a < 20$

----> $\frac{5a}{5} < \frac{20}{5}$

-----> $a < 4$

5.) $2t + 8 \geq -4(t + 1)$

--> $2t + 8 \geq -4t - 4$

---> $2t + 4t \geq -8 - 4$

----> $6t \geq -12$

-----> $t \geq -2$

7 0

3 years ago

Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer

Andrews [41]

Answer:

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,\frac{2}{3})$

$(x_2,y_2) = (3,\frac{5}{9})$

Required

Write the equation of the function $f(x) = ab^x$

Express the function as:

$y = ab^x$

In: $(x_1,y_1) = (2,\frac{2}{3})$

$y = ab^x$

$\frac{2}{3} = a * b^2$ --- (1)

In $(x_2,y_2) = (3,\frac{5}{9})$

$y = ab^x$

$\frac{5}{9} = a * b^3$ --- (2)

Divide (2) by (1)

$\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}$

$\frac{5}{9}/\frac{2}{3} = b$

$\frac{5}{9}*\frac{3}{2} = b$

$\frac{5}{3}*\frac{1}{2} = b$

$\frac{5}{6} = b$

$b = \frac{5}{6}$

Substitute 5/6 for b in (1)

$\frac{2}{3} = a * b^2$

$\frac{2}{3} = a * \frac{5}{6}^2$

$\frac{2}{3} = a * \frac{25}{36}$

$a = \frac{2}{3} * \frac{36}{25}$

$a = \frac{2}{1} * \frac{12}{25}$

$a = \frac{24}{25}$

The function: $f(x) = ab^x$

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

7 0

2 years ago

Helpppppp pllzzzzzzzzz

fgiga [73]

Answer:

The length of side of largest square is 15 inches

Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

<u>Area of square 1: 81 square inches</u>

$s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9$

<u>Perimeter of square 2: 48 inches</u>

$4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches$

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

$(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15$

Hence,

The length of side of largest square is 15 inches

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2 years ago

PLEASE HELP ME !! PLEASE !!

Yakvenalex [24]

I think that it is a ok

6 0

3 years ago