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Luda [366]
2 years ago
15

How much would it cost to buy 3 medium sodas and 2 hot dogs

Mathematics
2 answers:
Vesnalui [34]2 years ago
5 0

To start off you need to figure out how much money each item costs.  Now get out your calculator because it will make this process go much faster.



EXAMPLE:

If your sodas cost $2.25 EACH you need to do the following math equation

2.25 X 3 = 6.75 witch is the total you would be paying in this situation.


HOT DOGS EXAMPLE:


Lets say that your hotdogs are $4.75 PER DOG. You just need to follow the same steps above.


4.75 X 2 = 9.5 but thats not how we write money so it would be $9.50


Hope this helps,


Daniel

PSYCHO15rus [73]2 years ago
4 0

Answer:

depends what price it is

Step-by-step explanation:

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Answer: D) the last one

Step-by-step explanation:

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Angel has 8 DVD movies on a shelf, 2 dramas,5 sicence fiction movies, and 1 comedy. Two movies will be selected at random. Deter
mr Goodwill [35]

Answer:

A) Pd = 13/28

B) Pd = 7/16

Step-by-step explanation:

Given;

Drama = 2

Comedy = 1

Science fiction = 5

Total = 8

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Pd = 1 - Pd'

Without replacement;

Probability of not selecting a drama movie Pd' is;

Pd' = 6/8 × 5/7 = 15/28

Pd = 1 - 15/28

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b) with replacement;

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3 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
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P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
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  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
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2 years ago
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