16. The open circle is excluded and closed is included.
x≤-6
x>2
17. The open circle is excluded so the inequality would be: -3<x<2
So probability is (desired outcomes)/(total possitlble outcomes)
desired is 1 since 3 appaears once on the cube
6 total possible
so probaity of rolling a3 is 1/6
100 times
100 times 1/6=100/6=16 and 2/3 times
round up
17 times
Answer:
-25
Step-by-step explanation:
Using the commutative property of addition, we can rearrange the expression to 56-56-25. 56-56 = 0, so the answer is 0 - 25 = -25.
Y>3 only rules out B. B,D,E,F all satisfy 2x<y. So
ANSWER: D E F
Answer:
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Step-by-step explanation:
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