An algebraic expression is a mathematical expression that contains one or more
2 answers:
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The correct answer would be 
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.
In order to solve for this you must first get the equation equal to 0.
<span>x^2=-5x-3 ----> add 5x to both sides.
x^2 + 5x = -3 ----> add 3 to both sides.
x^2 + 5x + 3 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 5</span> (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
And those would be your two answers.
Answer:
Selling price of hockey game set is $145.32 , markup price is $210.54 and profit is $96 .
Step-by-step explanation:
Let us assume that the selling price of hockey game set be x .
As given
Pyotr Tchaikovsky Sporting Goods operates on a 45% overhead based on the selling price, which results in an overhead of $65.34 on the newest version of an air hockey game set.
45% is written in the decimal form .
= 0.45
Thus the equation becomes
0.45 × x = 65.34
0.45x = 65.34
x = 145.2
Therefore the selling price of the hockey game set is $145.2 .
Thus
Markup price = Selling price + Overhead Price
= $145.2 + $65.34
= $ 210.54
As given
If the air hockey game set costs Pyotr Tchaikovsky Sports $49.32 .
i.e Cost price of the hockey game set = $ 49.32
Profit = Selling price - Cost price
= 145.32 - 49.32
= $ 96
Therefore selling price of hockey game set is $145.32 , markup price is $210.54 and profit is $96 .