Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Pi is multiplied by diameter so,
35 x pi= 109.995
tell me how many decimal places should the finals should be so that I can round off
Area of rectangle = Length*width
A = 28 so 28 = 4 * height
height = 28/4 = 7
Answer:
Step-by-step explanation:
Explanation
6 sprinters are in a race. Any one of the 6 could win. None of them can win 2 medals. So the first result is 6
5 runners remain. The second medal goes to any one of the 5
4 runners remain after 1 of the 5 have been choosen. Any one of the 4 could win.
Answer 6 * 5 * 4 = 120
There are 120 ways of awarding 3 medals to 6 people.
