First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
Answer:
$637.95
Step-by-step explanation:
convert 8.5% to a decimal by dividing by 100:
8.5÷100= 0.085
then multiply.
587.98×(0.085)=49.97
now add.
587.98+49.97=<u>637.95</u>
Answer: to make 78 copies it cost 26 dollars.
Step-by-step explanation:
18 copies - 6 dollars
78 copies - x dollars
Hence,
Answer:
ABC is translated right 5 units and down 5 units
Step-by-step explanation:
The vertices of the original and new triangles haven't moved. Only the triangle as a whole moved from one place to another. The other choices involved reflecting the triangle in which the vertices change locations that are different from their original locations. Hope this helps!
Answer:
The quadratic function whose graph contains these points is 
Step-by-step explanation:
We know that a quadratic function is a function of the form 
. The first step is use the 3 points given to write 3 equations to find the values of the constants <em>a</em>,<em>b</em>, and <em>c</em>.
Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.
We can solve these system of equations by substitution
- Substitute
- Isolate a for the first equation
- Substitute
into the second equation
The solutions to the system of equations are:
b=-2,a=-1,c=-2
So the quadratic function whose graph contains these points is
As you can corroborate with the graph of this function.
