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Kobotan [32]
3 years ago
15

What is the unit form in (2 tens 1 one) ×10

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

we need to find the unit form in 2 tens and one multiplied with 10 .' we know that

21 is the 2 tens one

if we multiplied 21 with 10 we get 210 .

which means 21 tens are there in 210.which is the unit form of 210.

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50 POINTS! I MARK BRAINLEST AND SAY THANKS!
Phantasy [73]
Y *x =20

y +x =9

rewrite 1st eq. as y = 20/x

subsituute that into 2nd eq.

20/x +x =9

multiply each term by X

20 +x^2 = 9x
 subtract 9x from each side:

x^2 - 9x +20 = 0

now factor:

(x-5) (x-4) = 0

solve for x
5-5 = 0
 4-4 = 0

so X can be 4 or 5

replace x into equations and solve for Y

 so when X = 4, Y = 5
 When X = 5, Y = 4

x= 5,4
y = 4,5



5 0
3 years ago
Read 2 more answers
Helppppppppppppppppppppppppppppp
sukhopar [10]

Answer:

30 degress

Step-by-step explanation:

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7Bx%7D%5E%7B2%7D%20%2B%204x%20-%205" id="TexFormula1" title="f(x) = {x}^{2}
frutty [35]

The inverse function theorem says

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(f^{-1}(16))}

We have

f(x)=x^2+4x-5

defined on x>-2, for which we get

f^{-1}(x)=-2+\sqrt{x+9}

and

f^{-1}(16)=-2+\sqrt{16+9}=3

The derivative of f(x) is

f'(x)=2x+4

So we end up with

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(3)}=\dfrac1{10}

6 0
3 years ago
Pleaseeeee help me thank you
Lera25 [3.4K]
1) 3^3 * 4^3 = 12^3
2) 3^4 * 3^3 = 3^7
3) 3^4 * 4^3 = 12^12
They are all equal.
6 0
3 years ago
Read 2 more answers
. The 6 fourth-grade classes at
tensa zangetsu [6.8K]

Answer:

Each class donated $300

Step-by-step explanation:

1,792 has to be rounded to 1,800, because the answer is estimated, so 1,800 divided by 6 is 300

This might be wrong, but if not yw lol

8 0
3 years ago
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