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Kobotan [32]
3 years ago
15

What is the unit form in (2 tens 1 one) ×10

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0

we need to find the unit form in 2 tens and one multiplied with 10 .' we know that

21 is the 2 tens one

if we multiplied 21 with 10 we get 210 .

which means 21 tens are there in 210.which is the unit form of 210.

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Please help me with this problem​
Snowcat [4.5K]
The answer is -6x + 5y <_ -30
4 0
3 years ago
Help for brainiest and extra points !!!
aalyn [17]

Answer:

1. A, because 4(2)=8. 2 is the x.

2. B, because 2.5 x 4 = 10, which makes sense.

3. B, because 5x is the amount that you want to put into equal parts and the 3 is just being subtracted from the amount of the equal parts from the 5x.

4. C.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1
zloy xaker [14]

The value of y from the diagram is 9

<h3>Similar shapes</h3>

From the given figure, the shapes are similar, using the similarity theorem of triangles, you ill have;

6/10 = y/15

Cross multiply

10y = 15* 10

10y = 90

y = 90/10

y = 9

Hence the value of y from the diagram is 9

Learn more on similar shapes here: brainly.com/question/2644832

6 0
2 years ago
Read 2 more answers
Luis earns a base salary of \$150.00$150.00 every week with an additional 14\%14% commission on everything he sells. Luis sold \
tester [92]

Answer: Luis earned $997.00 for last week.

$6,050.00 - 14%= $5,203.00

Just figure the difference ($847)

Then add his base salary.

4 0
4 years ago
If a = {6 6 4 7 -4 4 -6 9 -3} and B= {1 5 -8 9 -5 -8 9 -5 2}, find 3a +9B Matrix operations
V125BC [204]

Answer:

3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}

Step-by-step explanation

  • A=\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix}\: and \: B=\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=3\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix},\:  \: 9B =9\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 3*6 & 3*6 & 3*4\\\\3*7 & 3(-4) & 3*4\\\\ 3(-6) & 3*9 & 3(-3)\end{bmatrix},\:\: 9B =\begin{bmatrix}9*1 &9* 5 &9( -8)\\\\ 9*9 & 9(-5) & 9(-8)\\\\ 9*9 & 9(-5) & 9*2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 18 & 18 & 12 \\\\ 21 & -12 & 12\\\\ -18 & 27 & -9\end{bmatrix},\:\: 9B =\begin{bmatrix} 9 & 45 & -72 \\\\ 81 & -45 & -72\\\\ 81 & -45 & 18\end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix}18+9 & 18+45 & 12+(-72) \\\\ 21+81 & -12 +(-45) & 12+(-72)\\\\ -18+81 & 27+(-45) & -9+18 \end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix} 18+9 & 18+45 & 12-72 \\\\ 21+81 & -12 -45 & 12-72\\\\ -18+81 & 27-45 & -9+18 \end{bmatrix}

  • \rightarrow \purple{\bold{3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}}}
6 0
2 years ago
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