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2 years ago

What is the unit form in (2 tens 1 one) ×10

Mathematics

1 answer:

Nonamiya [84]2 years ago

6 0

we need to find the unit form in 2 tens and one multiplied with 10 .' we know that

21 is the 2 tens one

if we multiplied 21 with 10 we get 210 .

which means 21 tens are there in 210.which is the unit form of 210.

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Find two whole numbers with a sum of 15 and a product of 54

likoan [24]

A+b=15----(1)
a*b=54----(2)

(1) a=15-b ----(3)

put(3) in(2)

(15-b)*b=54
15b-b^2=54
b^2-15b+54=0
(b-9)(b-6)=0
so b=9 or b=6

if b=9 then a=15-9=6
if b=6 then a=15-6=9

answer two numbers are 6 and 9

3 0

3 years ago

If (8^9)p = 8^16 what's the value of p?

monitta

Answer:

$p = {8}^{7}$

Step-by-step explanation:

$(8^9)p = 8^{16 } \\ \\ p = \frac{8^{16 } }{8^{9 } } \\ \\ p = {8}^{16 - 9} \\ \\ \huge \red{ \boxed{p = {8}^{7} }}$

8 0

2 years ago

How to identify the parent function given an equation ?

Anettt [7]

Answer:

You can identify the parent function by making the equation into its simplest form.

Step-by-step explanation:

Remove all transformations from the equation (such as plus/minus signs, constants, and extra terms in the equation).

ex. y= -3x^2+15

The parent function would be y=x^2 after removing everything.

Hope this helps! :)

8 0

3 years ago

Factor this expression completely, then place the factors in the proper location on the grid. 9x2 - y2

andreev551 [17]

Answer:

${ \tt{ {9x}^{2} - {y}^{2} }} \\ = { \tt{( {3x)}^{2} - {y}^{2} }} \\ = { \tt{(3x - y)(3x + y)}}$

6 0

2 years ago

The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40, 40, 48, 61, 72,

yawa3891 [41]

Answer:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

Step-by-step explanation:

The first step is to write the temperatures in crescent order:

40, 40, 42, 48, 54, 61, 65, 72, 76, 78, 84, 84,

The sample minimum is the lowest value = 40

The sample maximum is the highest value = 84.

Since there are 12 numbers, the sample median is the average between the 6th and 7th terms:

$M = \frac{61+65}{2}\\ M=63$

The first quartile is the average between the 3rd and 4th terms:

$Q_1 = \frac{42+48}{2}\\ Q_1=45$

The third quartile is the average between the 9th and 10th terms:

$Q_3 = \frac{76+78}{2}\\ Q_3=77$

Therefore, the answer is:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

8 0

2 years ago