The coefficients are 7.5 and 0.2. The variables are OH and OS, and the constant is 40. Good luck.
Answer:
Dude! Stop telling people to do your work on DeltaMath
Step-by-step explanation:
Let the origin of the coordinate system be the position of ship B at noon. Then the distance between the ships as a function of t (in hours) is
.. d = √((30 +23t)² +(17t)²)
.. = √(818t² +1380t +900)
The rate of change of distance with respect to time is
.. d' = (1/2)(2*818*t +1380)/√(818t² +1380t +900)
.. = (818t +690)/√(818t² +1380t +900)
At t=4, this is
.. d' = (818*4 +690)/√(818*16 +1380*4 +900)
.. = 3962/√19508
.. ≈ 28.37 . . . . . knots
The distance between the ships is increasing at about 28.37 knots at 4 pm.
A=LW(1/2)
is the standard formula, so plug in for variables
A=(30)(12)(1/2)
You simplify and get
A=180 in
So the complete answer is
-The area of the bandana is 180inches.
-10=5(2x-4)
-10=10x-20
+20 +20
10=10x
1=x