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vichka [17]
3 years ago
11

Find the value of x.

Mathematics
1 answer:
Rainbow [258]3 years ago
6 0

Answer:

60

Step-by-step explanation:

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Help please i don’t understand
kherson [118]

Answer:

20/29

Step-by-step explanation:

I hope that this 3 will help you understand easily.

4 0
2 years ago
Simplify -3/2 * 9/6<br><br> A. -4<br> B. -1<br> C. 4<br> D. 1
zalisa [80]

Answer:

-2.25

Step-by-step explanation:

8 0
2 years ago
Use the Ratio Test to determine whether the series is convergent or divergent. [infinity] n! 112n n = 1 Identify an. Correct: Yo
MakcuM [25]

Answer:

Step-by-step explanation:

Recall that the ratio test is stated as follows:

Given a series of the form \sum_{n=1}^{\infty} a_n let L=\lim_{n\to \infty}\left|\frac{a_{n+1}}{a_n}\right|

If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.

Consider the given series \sum_{n=1}^{\infty} n! \cdot 112n. In this case, a_n =n! \cdot 112n, so , consider the limit

\lim_{n\to\infty} \frac{(n+1)! 112 (n+1)}{n! 112 n} = \lim_{n\to\infty}\frac{(n+1)^2}{n}

Since the numerator has a greater exponent than the numerator, the limit is infinity, which is greater than one, hence, the series diverge by the ratio test

7 0
3 years ago
Find the value of 10! / (10-2) !
Gnesinka [82]

Answer:

90

Step-by-step explanation:

10! / (10 - 2)!

=10!/8!

=10 * 9 * 8! /8!

=90 * 8!/8!

90

Hope this helps. Please mark as brainliest if possible. Have a nice day

3 0
3 years ago
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

(4x-1)ln(e) =ln(3)

ln e as an inverse simplifies to 1.

(4x-1)(1)=ln(3)

We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
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