Hi there
The formula is
A=pe^rt
We need to solve for p where
A future value 15000
P present value?
E constant
R interest rate 0.059
T time 12 years
So when you solve for p you get
P=A÷e^rt
P=15,000÷e^(0.059×12)
P=7,389.43
Hope it helps
The answer is B due to the corresponding 130
Answer:
t= 12.9 years
Step-by-step explanation:
Value after t years = initial value ( 1 - r )^t
Where,
Value after t years= $5000
Initial value = $22,400
r= depreciation rate = 11%
t= length of time (years)
Value after t years = initial value ( 1 - r )^t
5000 = 22,400 ( 1 - 0.11)^t
5000 = 22,400(0.89)^t
Divide both sides by 22,400
(0.89)^t = 5000 / 22,400
(0.89)^t = 0.2232
Take the log of both sides
t log 0.89 = log 0.2232
t= log 0.2232 / log 0.89
= -0.6513 / -0.0506
= 12.87
t= 12.9 years
Answer:
the answer is B
Step-by-step explanation:
Answer:
y = 0.36x + 4200.00
15100.00 miles.
Step-by-step explanation:
If the yearly cost for driving x miles is given by y dollars then the two ordered pairs to find the linear relation between x and y are (10000,7800) and (20000,11400).
So, the equation will be
⇒ 
⇒ 
⇒ 
⇒ 
⇒ y = 0.36x + 4200.00 ........... (1) (Answer)
Now, for y = $9636.00, from equation (1),
9636 = 0.36x + 4200
⇒ 0.36x = 5436
⇒ x = 15100.00 miles. (Answer)
