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lilavasa [31]
3 years ago
13

How do I do this? Help????!!!

Mathematics
1 answer:
mylen [45]3 years ago
4 0
A = 9 because 11.2-2.2=9
B= 2.2 because 9+2.2=11.2
C=2.2 because 11.2-9=2.2
D=9.2 because 11.2-2=9


E=4.5 because 9.5-5=4.5
F= 5 because 9.5-4.5=5
G=4.5 because 9.5-5=4.5
H=5 because 9.5-4.5=5

I= x=11 because 99 divided by 9 = 11
J= x=9 because 99 divided by 11 = 9
K= 9 because 99 divided by 11 =9
L= 11 because 99 divided by 9=11

M=2 because 4 divided by 2 =2
N=4 because 2 times 2 =4
O=2 because 4 divided by 2 =2
P=2 because 4 divided by 2=2


hope this helps:)
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Write as an equation: Mike, Carroll, and Jim, empty their wallets and have $175 total. Mike has three times
Marina86 [1]

Answer:

  C.  j +2j + 3(2j) = 175

Step-by-step explanation:

Let j represent the amount of money Jim has.

Carroll has twice that amount, so has 2j.

Mike has 3 times the amount Carroll has, so has 3(2j).

The sum of these quantities is 175, so the equation can be written ...

  j + 2j + 3(2j) = 175 . . . . . matches choice C

7 0
3 years ago
Explain (1+y)^2 how does it turn into 1+2y+y^2 ? i don't understand
Greeley [361]
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
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6 0
3 years ago
Give an example of a number between 20 and 50 which is a multiple of 3 and also a factor of 84.​
Kazeer [188]

Answer:

69

Step-by-step explanation:

by eliminating 20 from 84 we get 64 then add the 3 to get 67 and then we know that we always add 2 to our answers and therefore get 69

6 0
3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
-5(4+2x)-14x simplify the expression
siniylev [52]

Answer:

− 20 − 24 x

Step-by-step explanation:

simplify

6 0
2 years ago
Read 2 more answers
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