If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is re
1 answer:
The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s
The free fall formula and the procedure we will use is:
fv = g* t
Where:
- fv = final velocity
- g = acceleration due to gravity
- t = time taken
- h = height traveled
Information of the problem:
- g = 9.8 m/s².
- t = 2 s
- vf = ?
Applying final velocity formula we get:
fv = g* t
fv = 9.8 m/s² * 2 s
fv = 19.6 m/s
<h3>What is free fall?</h3>It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.
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Answer:
E(final)/E(initial)=2
Explanation:
Applying the law of gauss to two parallel plates with charge density equal σ:
So, if the charge is doubled the Electric field is doubled too
E(final)/E(initial)=2