If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is re
1 answer:
The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s
The free fall formula and the procedure we will use is:
fv = g* t
Where:
- fv = final velocity
- g = acceleration due to gravity
- t = time taken
- h = height traveled
Information of the problem:
- g = 9.8 m/s².
- t = 2 s
- vf = ?
Applying final velocity formula we get:
fv = g* t
fv = 9.8 m/s² * 2 s
fv = 19.6 m/s
<h3>What is free fall?</h3>It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.
Learn more about free fall at brainly.com/question/11257529
#SPJ4
You might be interested in
Answer:
3.82 Ns
Explanation:
Time varying horizontal Force is given as
F(t) = A t⁴ + B t²
F(t) = 4.50 t⁴ + 8.75 t²
Impulse imparted is given as
Answer:
The horizontal component of the velocity is 188 m/s
The vertical component of the velocity is 50 m/s.
Explanation:
Hi there!
Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:
We can find vx using the following trigonometric rule of a right triangle:
cos α = adjacent / hypotenuse
cos 15° = vx / 195 m/s
195 m/s · cos 15° = vx
vx = 188 m/s
The horizontal component of the velocity is 188 m/s
To calculate the y-component we will use the following trigonometric rule:
sin α = opposite / hypotenuse
sin 15° = vy / 195 m/s
195 m/s · sin 15° = vy
vy = 50 m/s
The vertical component of the velocity is 50 m/s.
