Answer:
<em> The 99% confidence interval for the mean repair cost for the VCRs</em>
(65.801, 85.199)
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Mean of the sample(x⁻) = $75.50
Given the standard deviation of the sample (S) = $18.07
Given the size of the sample 'n' = 22
Degrees of freedom = n-1 =22-1 =21
critical value t₍₀.₀₁, ₂₁₎ = 2.5176
<em> The 99% confidence interval for the mean repair cost for the VCRs</em>
( 75.50 - 9.699 , 75.50 + 9.699 )
(65.801, 85.199)
<u><em>Final answer:-</em></u>
<em> The 99% confidence interval for the mean repair cost for the VCRs</em>
(65.801, 85.199)