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irina1246 [14]
3 years ago
5

What is the equation of the line that passes through the point (5,-2)and has a slope of the fraction 6/5?

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

6x-5y-40 = 0

Step-by-step explanation:

y-(-2)=6/5(x-5)

5(y+2)= 6(x-5)

5y+10 =6x-30

6x-5y-40 = 0

6x-5y-40 = 0 is the answer

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Plz help asap thank youuu
wariber [46]

Answer:

1. y = 0, b/a

2. y =  0, a/b

3. y =0, c/b

4. y =0, c/a

Step-by-step explanation:

The slope formula for y = mx + b which is known as standard form is Ax + By ≥ C

slope = A/B

x-intercept = C/A

y-intercept = C/B

and now we are dueling with y, so we will use y-intercept

1. cx + ay = b

where c is x, a = y and b=c

Y-int = C/B

y = 0, b/a

2. cx + by = a

y =  0, a/b

3. ax + by = c

y =0, c/b

4. bx+ ay = c

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Hope this helps

7 0
3 years ago
AC is tangent to circle O at point C. What is the length of OC
Sedaia [141]

Let OC is x, so OC=OB=x

{4}^{2}  + x^{2}  =  {(2 + x)}^{2}  \\ 16 +  {x}^{2}  = 4 + 4x +  {x}^{2}  \\ 12 = 4x \\ x = 3

Answer: OC=3 points

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3 years ago
HELPP PLS ILL MARK BRAINLIST
elena-14-01-66 [18.8K]

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Solve<br> 3(2x - 5) = 9(10 - x)
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Answer:

x=7

Step-by-step explanation:

3(2x - 5) = 9(10 - x)

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