Answer:
0.05 ; 0.28 ;0.51 ; 0 ; 6.95 ; 0.79
Explanation:
Given tbe probability distribution :
X= #sold_______0 ___5___ 10___ 15___ 20
Probability_P(x) 0.26_ 0.46 _0.07_ ...? ___0.16
A.) probability of selling 15 cheesecakes in a given day;
Sum of P(x) should add up to 1
ΣP(X) = 1
ΣP(X) = (0.26 + 0.46 + 0.07 + x + 0.16) = 1
x = 1 - 0.95
x = 0.05
B.) What is the probability of selling at least 10 cheesecakes?
P(x = 10) + P(x = 15) + P(x = 20)
0.07 + 0.05 + 0.16 = 0.28
C.) What is the probability of selling 5 or 15 chassescakes?
P(x =5) + P(x = 15)
0.46 + 0.05 = 0.51
D.) What is the probability of selling 25 cheesecakes?
Number of cheesecakes sold does not exceed 20`;
p(x = 25) = 0
E.) Give the expected number of cheesecakes sold in a day using the discrete probability distribution?
Σ(X * P(X))
(0.26 * 0) + (0.46 * 5) + (0.07 * 10) + (0.05 * 15) + (0.16 * 20) = 6.95
What is the probability of selling at most 10 cheesecakes?
P(x = 0) + P(x = 5) + P(x = 10)
0.26 + 0.46 + 0.07 = 0.79
