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STALIN [3.7K]
3 years ago
10

How is the Recursive Formula used in real life

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

People often sort stacks of documents using a recursive method. For example, imagine you are sorting 100 documents with names on them. First place documents into piles by the first letter, then sort each pile. Looking up words in the dictionary is often performed by a binary-search-like technique, which is recursive.

Step-by-step explanation:

This is just an example.

If this helps please mark as brainliest

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Can you please help me with 19 20 21 22 and look at the green bar that has all the info thank you
abruzzese [7]
19. 10 divided by 3 = 5 pounds
20. 5.5 divided by .5 = 11
21. no because 1.25 x 2.5 = 3.12 and she only has $3
22. the restaurant because the restaurant wants to buy 30lb and its $1.25 so 30 x 1.25 = 37.5  and the hotel buys 12 lb for $3 so that is 12 x 3= 36
3 0
3 years ago
Read 2 more answers
each morning, danai buys breakfast on her why to work. In the past thirty days, she bought a bagel on 6 days, a banana on 12 day
Ksju [112]

Answer:

  • 0.7 or 70%

Step-by-step explanation:

Total number of days

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The number of days she bought a banana or orange

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The probability of buying a banana or an orange is

  • P(b or o) = 21/30 = 0.7 = 70%
8 0
2 years ago
If a car's speed is 90km per hour, how many kilometers will it travel in 20 minutes?
frutty [35]
20 minutes* (1 hour/ 60 minutes)* (90 km/ 1 hour)= 30 km.
(Note that the units cancel out so you get the answer)

Final answer: 30 km~
3 0
4 years ago
What is the domain and range of the graph?
Tems11 [23]

Answer:

B

Step-by-step explanation:

5 0
4 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

8 0
3 years ago
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