Answer:
a) 8259888
b) 34220
c) 45057474
Step-by-step explanation:
Given,
The total number of transistor = 65,
In which, the defective transistor = 6,
So, the number of non defective transistor = 65 - 6 = 59,
Since, out of these transistor 5 are selected,
a) Thus, the number of ways = the total possible combination of 5 transistors =
b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors =
c) The number of sample without any defective transistor = The possible combination of 0 defective transistor =