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VMariaS [17]
3 years ago
12

Again. Did I solve the Matrices correctly. By the way it's multiplying matrices.

Mathematics
2 answers:
pychu [463]3 years ago
5 0
Yup, it looks good to me.
liberstina [14]3 years ago
3 0
I just used my Ti 84

it is correct except for 3rd number

should be
-3
-6
-16
8
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My brain small so could you plz anwser his 6/11+ 2/ 3
Lena [83]

Answer:

1 7/33

Step-by-step explanation:

6/11 + 2/3 --> We need a common denominator

--> 11 x 3 = 33

33 is our common denominator

6 x 3 = 18

2 x 11 = 22

18/33 + 22/33 = 40/33

Convert to a mixed number

=> 1 7/33

Thus, we have our answer.

4 0
3 years ago
9782 divided by 67 step by step Long division
Ipatiy [6.2K]
Here you go . 146 is the answer with the work shown.

8 0
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Abril earned a total of $60 mowing lawns around her neighborhood. she charges $8 an hour and received $20 in tips .use the equat
zmey [24]

Answer:

She spent 5 hours mowing lawns.

Step-by-step explanation:

To solve, we will just use some algebra

8h + 20 = 60 | Subtract 20 from both sides

8h = 40 | Divide both sides by 8

h = 5

We can confirm this by plugging it back into the original formula.

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5 0
3 years ago
A) f(x)<br> B) g(x)<br> C) h(x)
jeka57 [31]

Answer:

decreasing increasing decreasing function

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2 years ago
Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg
n200080 [17]

\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k

is conservative if there is a scalar function f(x,y,z) such that \nabla f=\vec F. This would require

\dfrac{\partial f}{\partial x}=y

\dfrac{\partial f}{\partial y}=x

\dfrac{\partial f}{\partial z}=3

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

f(x,y,z)=xy+g(y,z)

\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

f(x,y,z)=xy+h(z)

\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C

f(x,y,z)=xy+3z+C

so \vec F is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r

=f(5,7,-2)-f(1,2,3)=\boxed{18}

8 0
3 years ago
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