When you print handouts, the presentation is printed with one or more slides on each piece of paper. When you print handouts, it's best to have the presentation printed on them for those who can not view the presentation clearly to follow along with. This also serves as a great tool for people who missed the presentation to receive a handout later or for those there to take home and review.
The primary feature of a digital video camera is to records video as digital signals. A digital video camera picture out as of live settings, encrypting it into information that can be definite or transcoded into electronic photographic media. A typical digital camera contains of a lens, image sensor, storing media and a number of other characteristics that can be also be initiated on other cameras such as scalable aperture, filters and flash. High feature images and digital video slides can be put in storage and replicated on a computer, CD or writable DVD or on the internet in deprived of any loss of quality.
Answer:
The most popular method of robot programming is probably the teach pendant. ... To program the robot, the operator moves it from point-to-point, using the buttons on the pendant to move it around and save each position individually. When the whole program has been learned, the robot can play back the points at full speed.
Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
