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vladimir2022 [97]
3 years ago
13

Can someone answer me

Computers and Technology
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

D. 5,184,000

Explanation:

3000*1728= 5184000

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Write a calculator program that will allow only addition, subtraction, multiplication & division. Have the
ozzi

num1 = float(input("Enter the first number: "))

num2 = float(input("Enter the second number: "))

operation = input("Which operation are you performing? (a/s/m/d) ")

if operation == "a":

   print("{} + {} = {}".format(num1, num2, num1+num2))

elif operation == "s":

   print("{} - {} = {}".format(num1, num2, num1-num2))

elif operation == "m":

   print("{} * {} = {}".format(num1, num2, num1*num2))

elif operation == "d":

   print("{} / {} = {}".format(num1, num2, num1/num2))

I hope this helps!

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2 years ago
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Answer:

B

Explanation:

Every HTML document must begin with a declaration of what the document is going to be about.

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How does communication resolve problems​
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Answer:

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8 0
2 years ago
Read 2 more answers
1. During the first scene, Taylor's mother says "What you do online isn't exactly private." What do you think she meant by that?
tekilochka [14]

Answer:

The statement is "True".

Explanation:

Explanation of this statement can be given as:

  • Taylor's mother meant that the "universe is open to everything you do online, everyone can see". This statement true, because people will hack your profile unless you label these as personal, even re-post material that you have shared.  
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lapo4ka [179]

Answer:

Program to Plot  the power in Watts

voltage=1:200;

resistance=1000;

current=voltage/resistance;

power=current.*voltage;

plot(voltage,power);

xlabel('Voltage in Volts');

ylabel('Power in Watts'); //plot of this program is attached

Program for power in dBW

voltage=1:200;

resistance=1000;

current=voltage/resistance;

power=current.*voltage;

powerdB=10*log10(power);

plot(voltage,powerdB);

xlabel('Voltage in Volts');

ylabel('Power in dBW'); // plot output is also attached

I hope it will help you!

3 0
3 years ago
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