<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
x = 16
Step-by-step explanation:
5 = 1/2(x) - 3
Add 3 to both sides.
8 = 1/2(x)
Rewrite for clarity.
1/2(x) = 8
x/2 = 8
Multiply both sides by 2.
x = 16.
Proof:
5 = 1/2(x) - 3
Substitute variable.
5 = 1/2(16) - 3
Multiply 1/2 and 16.
5 = 8 - 3
Subtract 3 from 8.
5 = 5
Answer:
105 shifts
Step-by-step explanation:
Hourly net rate of pay = $12
1 shift = 8 hours
⇒ net pay per shift = $12 × 8 = $96
Total cost = tuition + residence + books
= $4500 + $4800 + $700
= $10,000
To calculate how many shifts Joanne needs to work, divide the total cost by the pay per shift and round it up:
Number of shifts = total cost ÷ net pay per shift
= $10,000 ÷ $96
= 104.1666666...
= 105 shifts
<u>Note</u>: we need to round up, as if Joanne works 104 shifts, she will earn $9,984 which is not quite enough to pay for tuition, residence and books.
Answer:where the numbers ? like a.3,b.5 somethin like that
Step-by-step explanation:
but its True
7/12>9/167
0.583333>0.053892
true
