Question

Evaluate the function for f(x) = x + 3 and g(x) = x2 – 2. (f + g)(t – 5)

Answer 1

Answer:

$(f+g)(t-5) = t^{2}-9t+21$

Step-by-step explanation:

(f+g)(t-5) = t-5+3+(t-5)^2-2

=t-2+t^2-10t+25_2

=T^2-9t+21

Answer 2

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$f(x) = x + 3$

$g(x) = {x}^{2} - 2$

_________________________________

$(f + g)(x) = f(x) + g(x)$

$(f + g)(x) = (x + 3) + ({x}^{2} - 2 )$

$(f + g)(x) = {x}^{2} + x + 3 - 2$

$(f + g)(x) = {x}^{2} + x + 1$

_________________________________

$(f + g)(t - 5) = ({t - 5})^{2} + (t - 5) + 1$

$(f + g)(t - 5) = {t}^{2} - 10t + 25 + t - 5 + 1$

Collect like terms

$(f + g)(t - 5) = {t}^{2} - 9t + 21$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️