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4 years ago

Help please!!!

Mathematics

1 answer:

notka56 [123]4 years ago

5 0

X=0. Y=-2. There is only one x value for this question.

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Mike bought 7 new baseball trading cards to add to his collection. His dog ate half of his collection. There are now only 25 car

RSB [31]

Answer:50

Step-by-step explanation:

Bc 25+25 is 50.

6 0

3 years ago

A line passes through the point -10,9 and has a slope of 1/2. Write an equation in slope-intercept form for this line

vitfil [10]

Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

y = (1/2)x + b

We want a value of b such that it forces the line to go through point (-10,9). Enter that point in the equation and solve for b:

y = (1/2)x + b

9 = (1/2)*(-10) + b

9 = -5 + b

b = 14

The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

y = (1/2)x + 14

See attachment.

7 0

3 years ago

For a school assembly student sit in chairs that are arranged in 53 rows. There are 12 chairs in each row. About how many studen

loris [4]

53x12=636 that is your answer that is the way to estimate it your answer is 636 that is how many students can be seated

6 0

3 years ago

Can you help me please help me

pashok25 [27]

Answer:

I can`t really see the question that well, but if I understand correctly here`s the first few.

1. Subtraction

2. Addition

3. Addition

4. Subtraction

5. Addition

6. Subtraction

It looks like its asking what is happening in those situations (is the number being added or subtracted). Sorry if that`s not much help

4 0

3 years ago

Can someone do this fast ? I need it for tomorrow

gregori [183]

Answer:

Step-by-step explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to $3x^2+x-1$ .

hg(x) = $x^2(x+2)$ which simplifies to

$x^3+2x^2$ . Now set that equal to $3x^2+x-1$ :

$x^3+2x^2=3x^2+x-1$ and get everything on the same side and factor:

$x^3-x^2-x+1=0$ . Factor by grouping:

$(x^3-x^2)-(x+1)=0$ and factor out what's common in each set of ( ):

$x^2(x-1)-1(x-1)=0$ which factors out to

$(x^2-1)(x-1)=0$ . But $x^2-1$ factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1

7 0

3 years ago