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3 years ago

Help please!!!

Mathematics

1 answer:

notka56 [123]3 years ago

5 0

X=0. Y=-2. There is only one x value for this question.

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What is the following product? Assume y >/= 0

spin [16.1K]

$\sqrt{y^3} * \sqrt{y^3}= \sqrt{y^3*y^3}= \sqrt{y^6}=y^{ \frac{6}{2} } =y^3$

7 0

3 years ago

Read 2 more answers

The wholesale price for a desk is $102. A certain furniture store marks up the wholesale price by 25%. Find the price of the des

denpristay [2]

Answer:

I guess $197.06

Step-by-step explanation:

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2 years ago

An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th

aliya0001 [1]

Answer:

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 17.42 ppm and a standard deviation of 3.25 ppm.

This means that $\mu = 17.42, \sigma = 3.25$

Sample of 12:

This means that $n = 12, s = \frac{3.25}{\sqrt{12}}$

Find the probability that the mean printing speed of the sample is greater than 18.12 ppm.

This is 1 subtracted by the p-value of Z when X = 18.12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{18.12 - 17.42}{\frac{3.25}{\sqrt{12}}}$

$Z = 0.75$

$Z = 0.75$ has a pvalue of 0.773.

1 - 0.773 = 0.227

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

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3 years ago

You know 1000 mg = 1g. Convert 2.5 grams into milligrams.

Nuetrik [128]

The answer is 2500 milligrams

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3 years ago

Now move the center of rotation, R, to a different position on the coordinate plane.

Scilla [17]

Answer: If the center of rotation is changed, the pentagon maps back onto itself only one time, when the value of a is 360 degrees that is, when the pentagon completes a full rotation. (just a heads up if your going to copy and paste, change it up a bit because this is word for word :) hope it helped!)

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3 years ago