<span>The correct answer is 'secondary consumer’. This is because the yellowfin tuna eats herbivorous fish (these are primary consumers - they only eat plants, which are producers) and take refuge from predators. This shows they are not tertiary consumers, as tertiary consumers are at the top of the food chain.</span>
Trichomoniasis is caused by a protozoan parasite that causes a mal/odorous frothy yellow to green discharge, itching (pruritus), and burning.
<h3>What is Trichomoniasis?</h3>
Trichomoniasis is a disease caused by a parasite whose symptoms are hugely variable among different persons.
Trichomoniasis is caused by the protozoan <em>Trichomonas vaginalis</em>, which infects suitable human hosts.
Trichomoniasis is a serious-mid disease and it must be treated properly in medical settings.
Learn more about Trichomoniasis here:
brainly.com/question/3129990
The features which create deposition from rivers are found in food plains, alluvial fan, and deltas.
Deposition is termed as a process whereby the transported materials by a river are being deposited.
When a river losses energy we say that there is deposition.
Where there is high flow of water in a river deposition is likely to occur because more sediments are being carried as well as erosion which is being caused.
Answer:
The answer is A
Explanation:
You can tell that rocks are older or younger depending on if other layers overlap. B is the oldest because all the others cover it, C is the second youngest because D and A overlap it. From what I could tell, when I took the test, it was either A or D, neither overlap each other so I was not sure so I guessed A and got it right. Though it could be looked at that A is smaller than D since its still growing and building.
Answer:
0.05 mg/mL ( B )
Explanation:
Given data:
20 mg/ml starch
2% solution = 2g of solute is in 100g of solvent
<u>Determine the new concentration in mg/ml </u>
Dilution equation = C1V1 = C2V2
new concentration ; applying the dilution factor
dilution factor = 1 : 400 ; ( 2 /400 )g = 0.005 g of solute is present in every 100 mL
∴ new concentration = 0.00005 g / 1 mL * ( 1000 mg / 1g ) = 0.05 mg/mL
