Answer:
x = √72 and yes, it forms a Pythagorean triple
Step-by-step explanation:
a^2 + b^2 = c^2,
3 is a, x is b, anf 9 is c
3^2 + x^2 = 9^2
9 + x^2 = 81
Subtract 9 from both sides
x^2 = 72
x = √72
a Pythagorean triple is a^2 + b^2 = c^2, and this has it
Answer:
The common difference would be calculated as:
(a21-a19)/2
(-164--(-58 ))/2 (Replacing the values )
(-164 +58)/2 (Changing signs)
(-106)/2(Subtracting)
-53
Then we are going to replace the common difference(d) in the sequence formal with the 21st term . It is done for finding the first term of the sequence.
a21=a0+d*(n-1)
-164=a0+-53*(21-1) (Replacing the values)
-164=a1-53(20) (Subtracting)
-164=a1-1060 (Multiplying )
-164+1060=a1 (Adding 1060 on both sides of the equation)
896=a1
The answer would be : an= 896-53*(n-1), which is the option B.
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Step-by-step explanation:
The initial image of the photo is 2 in by 4 in. The mat is 4 in by 6 in.
The new image is dilated by a scale of 2. So we double the dimensions. The new photo is 4 in by 8 in. The new mat is 8 in by 12 in.
Answer:
thx
Step-by-step explanation:
