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VLD [36.1K]
3 years ago
13

Which of the following is perfect square trinomial. Ive asked 4 times. Please Help. Will give brainlilest

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

D

Step-by-step explanation:

a perfect square trinomial is

a^2x^2\pm2(ab)xy+b^2y^2

factorized is

(ax\pm by)^2

so as you can see option A and B can't be, because they have -49y^2 and it has to be plus

so the other options are C and D

in the trinomial a=4 and b=\pm 7

the roots of a^2 and b^2

\pm2abxy=\pm2(4)(7)xy\\\\=\pm56xy

so it's option d with b=-7

16x^2-56xy+49y^2

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4 0
3 years ago
Write the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8).
mina [271]
Notice the picture below

\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad center\ ({{ h}},{{ k}})\qquad
radius={{ r}}\\\\
-----------------------------\\\\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
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5 0
3 years ago
Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta
Irina-Kira [14]

Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

y = f(u) in which u = g(x) is given by the following function.

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

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Is 2xy = -8 a function
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3 0
3 years ago
Read 2 more answers
5 + 3 . 3x-2 , let x=2
LiRa [457]

Answer:

8

Step-by-step explanation:

6 0
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