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denis-greek [22]
3 years ago
15

Science/math lol (PLEASE ACKNOWLEDGE THAT IT SAYS TWO FEATURES) ty

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

C and D I think??? Could be wrong. But definitely D is one of them.

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Tom [10]
+ 5ab is the answer...
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Quadrilateral ABCD is given, the interior angle at vertex B is 97 degrees and the exterior angle at vertex A is 88 degrees. Line
Citrus2011 [14]

Answer:

angle 1 = 83°

angle 2 = 88°

Step-by-step explanation:

angle 1 and angle on vertex B are

pair of co interior angles ( whose sum = 180° )

so, angle 1 + angle B = 180°

angle 1 = 180° - angle B

angle 1 = 180° - 97° = 83°

hence, angle 1 = 83°

but, angle 2 and exterior of vertex A forms alternate interior angle pair ,

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i hope you got it ....

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allochka39001 [22]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%
victus00 [196]

Let

\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}

The exponent is indeed 2n-1 - not a typo!

Take the antiderivative of f, denoted by F. This recovers a factor of 2n in the denominator, which lets us condense it to a single factorial.

\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}

Recall the series expansion of sine,

\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}

Then with a little algebraic manipulation, we get

\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x

Differentiate to recover f.

f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}

Finally, f(\pi) = \frac1\pi, so our sum is

\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}

3 0
1 year ago
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