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gayaneshka [121]
3 years ago
7

Is this right? plz help me

Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer:

no its the 3rd one

Step-by-step explanation:

thank me later

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3(2x-7=5-(1-x) pls help me
vekshin1

Answer:

 3 • (2x - 7) -  (x + 4)  = 0

then do 3.1     Pull out like factors :

  5x - 25  =   5 • (x - 5)

 5 • (x - 5)  = 0

4.2      Solve  :    x-5 = 0

Add  5  to both sides of the equation :

                     x = 5

Step-by-step explanation:

7 0
2 years ago
How would you graph this??<br><br> need help fast
statuscvo [17]

Answer:

There is no graph .... Please next time add one :)

Step-by-step explanation:

8 0
3 years ago
Define fn : [0,1] --&gt; R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
Plz help me i did it but messed up some ware plz help . 5x5=4x5+9=
Lyrx [107]

Answer: 25=29

Step-by-step explanation:5x5=25

4x5+9=29

5 0
3 years ago
Read 2 more answers
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zhuklara [117]

Answer:

Step-by-step explanation:

12\sqrt{11}=\sqrt{11*12*12}\\\\=\sqrt{1584}

6 0
3 years ago
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