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3 years ago

Suppose the slope of a line is positive. Describe what happens to the value of x as the value of y increases

Mathematics

2 answers:

Keith_Richards [23]3 years ago

6 0

A line with a positive slope has a positive increase in x associated with a positive increase in y

lana [24]3 years ago

5 0

As y increases, x will also increase because the slope of the line is positive. When the slope is positive, the x will always increase but if the slope is negative, the x will always decrease.

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Anni [7]

X=69 for the second one

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3 years ago

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Bell ringer

Kazeer [188]

Answer:

D.) 0.25

Step-by-step explanation:

Because it is not a whole number and decimals don't count as integers

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2 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

Did I do this question right ? If not explain why I tried and but not sure .....

kolbaska11 [484]

Answer:

almost

Step-by-step explanation:

-4 <= x < 0

at least includes the number, less than does not include the number.

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3 years ago

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Drupady [299]

Answer: $d(r) = 5(0.87)^r$

Step-by-step explanation:

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3 years ago