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antoniya [11.8K]
2 years ago
7

What is the answer to 40x 2/6 Explain how u got the answer also

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
8 0
The fraction form of this is 40/3, decimal form is 13.3 infinite.
Use whichever form your teacher wants you to use. (Refer to the image for the steps)

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The answer is A :)
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3 years ago
Convert each radian measure into degrees
faltersainse [42]

Answer:

Step-by-step explanation:

\frac{deg}{rad}=\frac{360}{2\pi }\\ \\ deg=\frac{360rad}{2\pi }\\ \\ deg=\frac{180rad}{\pi }

4 0
3 years ago
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
andriy [413]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

(c) Standard deviation of defective light bulbs = 3.67

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

Standard deviation of defective light bulbs is given by = S.D. = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.67

8 0
3 years ago
In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Muskan's scores i
Elanso [62]

Answer:

35

Step-by-step explanation:

To find his total score in the quiz, we need to add all the scores he had in successive rounds.

This gives a value of; 25 + (-5) + (-10) + 15 + 10 = 25-5-10+15+10 = 25 + 10 = 35

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3 0
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Solve the following equation for y. Y= 2y+4y-3=27
sammy [17]

Answer:

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4 0
3 years ago
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