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3 years ago

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The formula for the area of a rectangular piece of paper is , where is the length and is the width of the piece of paper. What i

s the area of a piece of paper with a length of centimeters and a width of centimeters ?

1 answer:

Andreyy893 years ago

7 0

Step-by-step explanation:

you multiply the length time the width

the answer would be in cm^2

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Translate 22% of b into an expression

romanna [79]

Answer:

11/50b

Step-by-step explanation:

22% of b = 22/100×b

= 11/50b

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3 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Natasha2012 [34]

Answer:

$x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$ are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

$2x^2-10x-3$

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

$x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}$

General form of quadratic equation is $ax^2+bx+c$

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

$D=\sqrt{(-10)^2-4(2)(-3)}$

$\Rightarrow D=\sqrt{100+24}=\sqrt{124}$

Now substituting D in $x=\frac{b^2\pm\sqrt{D}}{2a}$ we get

$x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}$

$x=\frac{100\pm\sqrt{124}}{4}$

$x=\frac{100\pm2\sqrt{31}}{4}$

$x=\frac{50\pm\sqrt{31}}{2}$

Therefore, $x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$

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3 years ago

Read 2 more answers

Convert the length of 7 centimeters to meters. Compare the numerical values when both numbers are written in scientific notation

Pie

I think you did correct.

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3 years ago

The distance from Portland to Seaside is 75 miles what is the distance in inches on the map which scale of 1.25 in:25 mi

jek_recluse [69]

Answer:

1.25in/25mi = x/75mi

25x = 93.75

x = 3.75

<u>3.75 inches</u>

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3 years ago

Which is greater 192 inches or 5yards and 1 foot

makvit [3.9K]

1 yard = 36 inches. We have 5 yards, so 5x36 = 180

1 foot = 12 inches.

So the base 192 is largest.

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3 years ago